HD 102329 b

By Brandon New Period #3 Note: This is something I made for my Physics class, please do not alter this page.

Description
The planet HD 102329 b is a giant exoplanet that orbits a K-type star more specifically names HD 102329. It's discovery was announced back in 2011 using radial velocity method, which measures the gravitational wobbles of the star caused by the planet's orbit. It has a mass that is around 0.65 times larger then Jupiter (8.51×10^27 Kg.). It has an Eccentricity of 0.21 with a Semi-Major Axis of 2.706×10^11 m. and a Semi-Minor Axis of 2.646×10^11 m. The planet's atmosphere is thought to be primarily composed of hydrogen and helium, with other elements such as carbon and oxygen likely present in smaller amounts. Due to its large size and high temperatures, it's likely that HD 102329 b doesn't have a solid surface, and instead has a thick, gaseous atmosphere. However, not much is known about the planet beyond its basic characteristics, as it has not been extensively studied.

Gravitational Force Between Star and Object (N)
To find the Gravitational Force between HD 102329 b and its star HD 102329 we must use the following formula:(Gravitational Constant × Mass of first object × Mass of the second object) / (Distance between the center of two bodies)^2

We already know that the mass of the planet is 8.51×10^27 Kg. all we have to do is find the mass of the Sun and the distance of the two objects which in this case is 2.586×10^30 Kg. and 2.706 m. respectively.

After subsisting the numbers in we are left with 2.00×10^25 N.

Orbital Period (s)
To find the orbital period of any object in space we must use the formula: ((4π^2)/(Gravitational Constant × Mass of the Star))*((Distance between the Star and the Object^3).

Once you plug in all the variables you should be left with 6.73×10^7 s.

Path Distance (m)
To find the Path Distance we must first find the Semi-Minor Axis (b) using the formula sqrt(((e×a)^2-a^2)/-1) to get b=2.646×10^11 m. e=Eccentricity (0.21) and a=Semi-Major Axis(2.706×10^11 m.)

After that we plug the numbers into the formula: 2π×sqrt((a^2+b^20/2)) to get 4.50×10^23 m.

Escape Velocity (m/s)
To find the Escape Velocity you will use the formula sqrt((2×Gravitational Constant×Mass of the Planet)/Radius of the Planet). The radius of the planet is 7.83×10^7m. and if we plug it in to the formula we will get 1.21×10^5 m/s.

Object Orbit Velocity (m/s)
You must use the formula sqrt((Gravitational Constant×Mass of the Sun)/Distance between the star and plane) to get 2.52×10^4 m/s.